На рисунке построен график функции у=f(x) c убывающей определением {-3; 5]
найдите область значения этой функции
1 [-1; 2]
2[-2; 5]
3[-2; 4]
4[-1; 5]

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а)

2х+3(2х+5)=31

2х+6х+15=31

8х+15=31

8х=31-15

8х=16

х=2

у=2*2+5

у=9

(х,у)=(2, 9)

б)

5(-3у+4)-7у=-24

-15у+20-7у=-24

-22у+20=-24

-22у=-24-20

-22у=-44

у=2

х=-3*2+4

х=-2

(х,у)=(-2, 2)

в)

2х+5у=-8

2х=-4-3у

-4-3у+5у=-8

-4+2у=-8

2у=-8+4

2у=-4

у=-2

2х=-4-3*(-3)

2х=-4+6

2х=2

х=1

(х,у)=(1, -2)

г)

-3х+7у=29

х=13/6-5/6 у

-3(13/6-5/6 у)+7у=29

-13/2+5/2 у+7у=29

-13/2+19/2 у=29 |*2

-13+19у=58

19у=58+13

19у=71

у=71/19

х=13/6-5/6*71/19

х=-18/19

(х,у)=(-18/19, 71/19)

д)

3х+7у=-5

х=7/5-4/5у

3(7/5-4/5у)+7у=-5

21/5-12/5у+7у=-5

21/5+23/5у=-5 |*5

21+23у=-25

23у=-25-21

23у=-46

у=-2

х=7/5-4/5*(-2)

х=3

(х,у)=(3, -2)