:y=-x2+4x-5 построить график функции .

1) 6x^2 - 12 = 0

6(x^2 - 2) = 0

x^2 = 2

x = ±√2

2)   3a^2 + 5a + 2 = 0

d = b^2 - 4ac = 25 - 4 * 3 * 2 = 25 - 24 = 1, √d = 1.

a1 = (-5 + 1) / 6 = -4/6 = -2/3

a2 = (-5 - 1) / 6 = -1

3) 4x + 4x^2 + 1 = 0

4x^2 + 4x + 1 = 0

d = k^2 - ac (вторая формула для нахождения дискр.) = 2^2 - 4*1 = 0

x1 = -2 + 0 / 4 = -0,5

4) 3x^2 + 7x - 6 = 0

d = b^2 - 4ac = 49 - 4 * 3 * (-6) = 49 +72 = 121, √d = 11

x1 = -7 + 11 / 6 = 4/6 = 2/3

x2 = -7 - 11 / 6 = -3

5) 5x^2 - 22x - 15 = 0

d = k^2 - ac = 11^2 - 5 * (-15) = 121 + 75 = 196, √d = 14

x1 = 11 + 14 / 5 = 25 / 5 = 5

x2 = 11 - 14 / 5 = -3/5 = - 0,6

6) 3x^2 - 10x + 9 = 0

d = k^2 - ac = 25 - 3 * 9 = 25 - 27 = -2, √d < 0, корней нет.

[tex]{x}^{2} - 9x + 20 = 0 \\ x(1) = 5 \\ x(2) = 4[/tex][tex]21 {x}^{2} - 2x - 3 = 0 \\ {x}^{2} - 2x - (3 \times 21) = 0 \\ {x}^{2} - 2x - 63 = 0 \\ 21x(1) = 9 \\ 21x(2) = - 7 \\ x(1) = \frac{9}{21} = \frac{3}{7} \\ x(2) = \frac{ - 7}{21} = \frac{ - 1}{3}[/tex][tex](3x + 1)(9 {x}^{2} - 3x + 1) - (9 {x}^{2} + 2)(3x - 2) = 16 {x}^{2} + 1 \\ 27 {x}^{3} + 1 - 27 {x}^{3} + 18 {x}^{2} - 6x + 4 - 16 {x}^{2} - 1 = 0 \\ 2 {x}^{2} - 6x + 4 = 0 \\ {x}^{2} - 3x + 2 = 0 \\ d = 9 - 8 = 1 \\ x(1) = 2 \\ x(2) = 1[/tex]сделай этот ответ лучшим, !